C#-继承的类转换

namespace DynamicGunsGallery
{
    public class Module
    {
        protected string name;

        public virtual string GetName() { return name; }
        public virtual string GetInfo() { return null;  }
    }
}

我创建了从基类继承的动态库,例如(AK47.dll)

namespace DynamicGunsGallery
{
    public class AK47 : Module
    {
        public AK47() { name = "AK47";  }

        public override string GetInfo()
        { 
            return @"The AK-47 is a selective-fire, gas-operated 7.62×39mm assault rifle, first developed in the USSR by Mikhail Kalashnikov.
                    It is officially known as Avtomat Kalashnikova . It is also known as a Kalashnikov, an AK, or in Russian slang, Kalash.";
        }
    }
}

我正在使用此(inspired by this link)加载动态库：

namespace DynamicGunsGallery
{
    public static class ModulesManager
    {
        public static Module getInstance(String fileName)
        {
            /* Load in the assembly. */
            Assembly moduleAssembly = Assembly.LoadFile(fileName);

            /* Get the types of classes that are in this assembly. */
            Type[] types = moduleAssembly.GetTypes();

            /* Loop through the types in the assembly until we find
             * a class that implements a Module.
             */
            foreach (Type type in types)
            {
                if (type.BaseType.FullName == "DynamicGunsGallery.Module")
                {
                    //
                    // Exception throwing on next line !
                    //
                    return (Module)Activator.CreateInstance(type);
                }
            }

            return null;
        }
    }
}

我在包含ModuleManager的可执行文件和dll库中都包含了基类.编译时没有问题,但是运行此代码时出现错误：

InvalidCastException was unhandled.

Unable to cast object of type DynamicGunsGallery.AK47 to type
DynamicGunsGallery.Module

所以问题是：为什么我不能将派生类转换为基类？

还有其他方法可以使用基类中的方法加载动态库并对其进行“控制”吗？

在您的子库中,您无法重新声明模块；您必须引用原始库中的模块.

在其中具有ak类的项目中添加对主项目的引用.

我还考虑更改命名空间,以使您很明显地看到正在运行两个库